Question 218682
If Juan has 4 more than twice the amount of nickels as sam and carlos has 2 less than 3 times the amount of nickels as sam and the total value of all 3 boys is 1.90, than how many nickels does sam have?


Let amount of nickels that Sam has be S

Since Juan has 4 more than twice Sam's amount, then Juan has 2S + 4

Since Carlos has 2 less than 3 times Sam's amount, then Carlos has 3S - 2


Together, the 3 boys have: S + 2S + 4 + 3S - 2, or (6S + 2) nickels


Now, since the value of all their nickels is $1.90, then we have:


.05(6S + 2) = 1.9


.3S + .1 = 1.9


.3S = 1.8


Therefore, {{{S = 1.8/.3}}}, which means that Sam has {{{highlight_green(6)}}} nickels.