Question 218663
If vehicles are going in opposite directions, they can be treated
as 1 vehicle going at the combined speed of both
{{{d = r*t}}}
{{{190 = (r + 2r)*2}}}
Note that I made things easy by calling rate {{{r + 2r}}}
{{{190 = 6r}}}
{{{r = 31.667}}}
This is the speed of the slower vehicle
in km/hr
{{{31.667}}}km/hr x {{{1/3600}}}hr/sec x {{{1000}}} m/km 
{{{31.667 * (1/3600) * 1000 = 8.796}}} m/s
The slower car is going 8.796 m/sec
check answer:
{{{2r = 17.593}}} m/s
{{{190 * 1000 = (17.593 + 8.796)*2*3600}}}
{{{190000 = 26.389 * 7200}}}
{{{190000 = 189997.867}}}
Close enough