Question 218525
Find four consecutive even integers such that three times the sum of the second integer and the fourth integer is 192.
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1st: 2x-2
2nd: 2x
3rd: 2x+2
4th: 2x+4
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Equation:
3(2x+2x+4) = 192
4x+4 = 64
4x = 60
x = 15
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1st: 2x-2 = 28
2nd: 2x = 30
3rd: 2x+2 = 32
4th: 2x+4 = 34
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Cheers,
Stan H.