Question 218499
The sum of three times the least of three consecutive integers and the greatest is 46. What are the three integers?


Step 1.  Let n be an integer and 3n be three times the least of 3 consecutive integers


Step 2.  Let n+1 and n+2 be the next two consecutive integer.


Step 3.  Let 3n+n+2=46 since the sum of three times the least of three consecutive integers and the greatest is 46.


Step 4.  Solving yields the following steps:


{{{4n+2=46}}}


Subtract 2 from both sides of the equation


{{{4n+2-2=46-2}}}


{{{4n=44}}}


Divide 4 to both sides of the equation


{{{4n/4=44/4}}}


{{{n=11}}} {{{n+1=12}} and {{{n+2=13}}}


Check 2n+n+2=46...3*11+13=46...which is a true statement.


Step 5.  The integers are 11, 12, and 13.


I hope the above steps were helpful.


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And good luck in your studies!


Respectfully,
Dr J