Question 218408
Four consecutive even integers whose sum is 120.


Step 1.  Let n be one even integer.


Step 2.  Let n+2, n+4, and n+6 be the next three consecutive integers.


Step 3.  Let n+n+2+n+4+n+6=120 since the sum of four even and consecutive even integers is 120.


Step 4.  Solving yields the following steps.


{{{4n+12=120}}}


Subtract 12 from both sides of the equation.


{{{4n+12-12=120-12}}}


{{{4n=108}}}


Divide by 4 to both sides of the equation.


{{{4n/4=108/4}}}


{{{n=27}}} and {{{n+2=29}}} {{{n+4=31}}} {{{n+6=33}}}


Check their sum...27+29+31+33=120...which is a true statement.


Step 5.  ANSWER:  The numbers are 27, 29, 31, and 33.


I hope the above steps were helpful.


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And good luck in your studies!


Respectfully,
Dr J

http://www.FreedomUniversity.TV