Question 218365
Recall that by definition {{{abs(a+bi)=sqrt(a^2+b^2)}}}



This tells us that {{{abs(6-8i)=sqrt(6^2+(-8)^2)=sqrt(36+64)=sqrt(100)=10}}}



So {{{abs(6-8i)=10}}}



Note: this represents the distance from (0,0) to (6,-8)