Question 218316
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Since each boat is traveling at a 10 mph steady state, the boats are closing with each other at a rate of 20 mph.  That means that the distance between them will be reduced to zero in 2 hours.  (40 miles divided by 20 mph is 2 hours).  Now I don't know what a pegion or a pigion is, but presuming you actually meant pigeon, the bird would be flying at a steady state of 25 mph for 2 hours, or 50 miles would be the theoretical distance traveled.  Of course that presumes the completely ludicrous idea that a bird of any kind can actually be traveling 25 miles per hour in one direction and then instantaneously reverse its direction and begin flying 25 miles per hour in the opposite direction.  In practical terms, the distance traveled by the bird would be much less because of the time it would actually take for the animal to slow down, stop, turn around, and reacquire speed again.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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