Question 218132
Let  x   &y  =  numbers
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x=6y
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2(x+y) = xy,,,,,,,,substitute
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2{6y+y} ={6y}y
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14y =6y^2
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0=6y^2 -14y
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0 = y(6y-14) =0
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y=0,,,,,,,,,y=14/6 = 7/3
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x=0,,,,,,,,,x= 14
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check,,,,(0,0),,,,0=0,,,,,ok,,,but  not  positive  number
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(14,7/3),,,,,2(14+7/3) = (14)(7/3) = 32.67,,,,,ok
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