Question 218076
Hint: Let {{{z=x+3}}} and use that substitution to get {{{z^2-2z+35}}}. Now see if you can factor {{{z^2-2z+35}}}. Note: once you're done factoring {{{z^2-2z+35}}}, don't forget to plug in {{{z=x+3}}} (to go back to variables in 'x').