Question 217401
Solve the equation by any system:


{{{x = 3y/2 + 5}}} or equivalently {{{2x-3y=10}}} where we multiplied by 2 to both sides of the equation to get rid of the denominator and subtracted 3y from both sides of the equation.

So we now have 

{{{2x -3y=10}}}   Equation A 
{{{2x - 3y = 11}}}  Equation B


We see that the left side of Equations A and B are identical.  So when we subtract equation A from Equation B, we have 0=1 or subtract B from equation A and we get 0=-1 which are not true statements.


ANSWER:  As a result, there is no solution to this equation.


I hope the above steps were helpful. 


For free Step-By-Step Videos on Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra or for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.


And good luck in your studies!


Respectfully,
Dr J