Question 217304
The answer is {{{(15!) / ((2!)*(13!)) = (15*14)/(1*2) = 105}}}
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To make it easier to show, assume it was 5 candidates for 2 positions.
The formula would then be {{{(5!) / ((2!)*(3!)) = (5*4)/(2*1) = 10}}}
Let the 5 candidates be abcde
Then the possible ways they could be chosen would be:
ab
ac
ad
ae
bc
bd
be
cd
ce
de
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Same concept applies with larger numbers.
Your answer is 105 different ways.
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The general formula for x positions chosen out of n candidates is:
{{{(n!)/((n-x)!*(x)!)}}}
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