Question 217280
There are two ways to do this, here's one way:



{{{a(x-5)=9x-25-2x-10}}} Start with the given equation.



{{{a(x-5)=7x-35}}} Combine like terms.



{{{a(x-5)=7(x-5)}}} Factor out the GCF 7 from the right side.



{{{(a*cross((x-5)))/cross((x-5))=(7cross((x-5)))/cross((x-5))}}} Divide both sides by {{{x-5}}}.



{{{a=7}}} Simplify



So the value {{{a=7}}} makes {{{a(x-5)=9x-25-2x-10}}} an identity. Go ahead and try to solve {{{7(x-5)=9x-25-2x-10}}} to confirm the answer.