Question 217267
The perimeter of a rectangular field is 158 feet. If the length is 10 more than twice the width, find the length and the width.


Step 1.  Perimeter P is when adding up all the sides of the rectangular.


Step 2.  Let w be the width.


Step 3.  Let 2w be twice the width


Step 4.  Let 2w+10 be the length since the length is 10 more than twice the width.


Step 5.  Then {{{P=w+w+2w+10+2w+10=6w+20=158}}}.


Step 6.  Solving the equation in Step 5 yields


Subtract 20 from both sides of the equation


{{{w+w+2w+10+2w+20-20=6w+10=158-20}}}


{{{6w+20-20=158-20}}}


{{{6w=138}}}


Divide 6 to both sides of the equation


{{{6w/6=138/6}}}


{{{w=23}}}


Then {{{2w+10=56}}}


Check...P=2(23+56)=158...which is a true statement...


Step 7. ANSWER:  The width is 23 feet and the length is 56 feet.


I hope the above steps were helpful. 


For free Step-By-Step Videos on Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra or for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.


And good luck in your studies!


Respectfully,
Dr J