Question 217225
What you're looking for here is the LCM of the numbers 1, 2, 3, 4, 5, 6, 7, 8, and 9





First, list the prime factorization of each number. If you need help with prime factorization, check out this <a href="http://www.algebra.com/algebra/homework/divisibility/factor-any-number.solver">solver</a>.



1: 1



2: 2



3: 3



4: 2*2



5: 5



6: 2*3



7: 7



8: 2*2*2



9: 3*3



Now highlight the unique factors. Remember, highlight the factors that occur most frequently



1: 1



2: 2



3: 3



4: 2*2



5: <font color="red">5</font>



6: 2*3



7: <font color="red">7</font>



8: <font color="red">2*2*2</font>



9: <font color="red">3*3</font>



Now multiply all of the highlighted factors


2*2*2*3*3*5*7=2520


So the LCM of 1, 2, 3, 4, 5, 6, 7, 8, and 9 is 2520



This means that the number 2,520 is the smallest positive integer that is divisible by 1, 2, 3, 4, 5, 6, 7, 8, and 9