Question 3677
what do you want? to factorise it?


{{{3(x^3 + 27)}}}
{{{3(x^3 + 3^3)}}}


now, {{{a^3 + b^3}}} is equivalent to {{{(a+b)(a^2-ab+b^2)}}}, so for ours, we get:


{{{3(x+3)(x^2-3x+9)}}}


jon.