Question 216931
given the function f(x)=-x^2+2x-3

find f(2)-2*f(0)


Since {{{f(x) = - x^2 + 2x - 3}}}, then {{{f(2) = - (2)^2 + 2(2) - 3 = - 4 + 4 - 3 = - 3}}}


Since {{{f(x) = - x^2 + 2x - 3}}}, then {{{2*f(0) = 2 * (0 + 0 - 3) = 2 * (- 3) = - 6}}}


Therefore, f(2)-2*f(0) = - 3 - (- 6) = - 3 + 6 = {{{highlight_green(3)}}}