Question 216960
What are the five consecutive whole numbers that add up to 225.


Step 1.  Let n, n+1, n+2, n+3, n+4 be the five consecutive whole numbers.


Step 2.  Then, n+n+1+n+2+n+3+n+4=5n+10=225 since these numbers add to 225.  


Step 3.  Subtract 10 from both sides of the equation in Step 2.


{{{5n+10-10=225-10}}}


{{{5n=215}}}


Divide 5 to both sides of the equation


{{{5n/5=215/5}}}


{{{n=43}}}  {{{n+1=44}}}  {{{n+2=45}}}  {{{n+3=46}}}  {{{n+4=47}}}


Check sum...43+44+45+46+47=225...a true statement.


Step 4.  ANSWER:  The five consecutive integers are:  43, 44, 45, 46, and 47.


I hope the above steps and explanation were helpful. 


For Step-By-Step videos on Introduction to Algebra, 

please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra and 

for Trigonmetry please visit 

http://www.FreedomUniversity.TV/courses/Trigonometry. 


Also, good luck in your studies and contact me at 

john@e-liteworks.com for your future math needs.


Respectfully, 
Dr J