Question 216931
Given:
{{{f(x) = x^2+2x-3}}} find:
{{{f(2)-2f(0)}}}
{{{f(2) = (2)^2+2(2)-3}}}
{{{f(2) = 4+4-3}}}
{{{f(2) = 5}}}
{{{f(0) = 0^2+2(0)-3}}}
{{{f(0) = -3}}}
{{{f(2)-2f(0) = 5-2(-3)}}}
{{{f(2)-2f(0) = 5+6}}}
{{{highlight(f(2)-2f(0) = 11)}}}