Question 216710
how do you graph:


{{{6x-5y+20=0}}}?


Step 1.  A relatively easy way is pick two point and plot a line between the two points.  Two points could be (0,b) and (a,0) where b is the y-intercept and a is the x-intercept.


Step 2.  Let's start with (0,b) where x=0 and y=b.  Substitute x=0 into


{{{6x-5y+20}}} or in standard form as {{{6x-5y=20}}}


{{{6*0-5y=20}}}


Divide by -5 to both sides of the equation


{{{-5y/-5=20/-5}}}


{{{y=-4}}} or {{{y=b=-4}}}


So we have point (0,-4)


Step 3.  Let's start with (a,0) where x=a and y=0.  Substitute y=0 and solve for x=a.


{{{6x-5y=20}}}


{{{6x-5*0=20}}}


{{{6x=20}}}


Divide by 6 on both sides of the equation.


{{{6x/6=20/6}}}


{{{x=20/6=10/3=a}}}


Now we have another point (10/3,0).


Step 4.  We now have two points to plot:  (0,-4)and (10/3,0) found in Steps 2 and 3.  Use these points to draw a line as shown below:


{{{graph(400,400, -10,10,-10,10, 6x/5-4)}}}


I hope the above steps were helpful. 


For free Step-By-Step Videos on Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra or for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.


And good luck in your studies!


Respectfully,
Dr J