Question 29620
If I read you right he started with 7 horses.
Start= x horses
After 1st toll he has x-(x/2)-(1/2)=(x/2)-1/2=(x-1)/2 horses
After 2nd toll he has [(x-1)/2 - (x-1)/4 -(1/2)]= (x-3)/4 horses
After 3rd toll has has [(x-3)/4 - (x-3)/8 -(1/2)]= (x-7)/8 horses
This last number must be zero.
So (x-7)/8=0
x-7=0
x=7 horses (number to start with.
Cheers,
Stan H.
T