Question 216636
I'll give you a hint to get started



First, note that there are {{{x^2}}} and {{{y^2}}} terms.



So take the second equation {{{x^2+y^2=2x+19}}} and solve for either {{{x^2}}} or {{{y^2}}}. I'm going to choose {{{y^2}}}. So solve for {{{y^2}}} to get {{{y^2=-x^2+2x+19}}}



Now simply plug in {{{y^2=-x^2+2x+19}}} into {{{x^2+2y^2=33}}} to get



{{{x^2+2(-x^2+2x+19)=33}}}



Now just solve the equation above to find 'x' and then use the value(s) of 'x' to find the corresponding value(s) of 'y'.