Question 216572
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I don't know what inte<b>r</b>gers are.  But I will presume you meant <i>integers</i>.


Let *[tex \Large x] represent the smaller of two consecutive odd integers.


If you add 1 to that, you get the next consecutive integer, but it is even.  If you add 2, you get the next consecutive odd integer.


Then *[tex \Large x + 2] must represent the larger of the two integers.


3 times the smaller is *[tex \Large 3x]


Twice the larger is *[tex \Large 2(x + 2) = 2x + 4]


So:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 3x = (2x + 4) + 13]


Solve for *[tex \Large x] to get the smaller integer.  Add 2 to get the larger one.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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