Question 216529
 Hi, I need some help with my American School Algebra 2 work. 
Given x^3-4x^2+2x+1=0 
A. How many possible positive roots are there?
Using Decartes' rule, there are either 2 or 0 positive roots.
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B. How many possible negative roots are there?
Descartes again, 1 negative root.
You can find Descartes on google.
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C. What are the possible rational roots?
+1 is a root.  I found it by graphing the function.
Then dividing it out, you're left with
x^2-3x-1 = 0
*[invoke solve_quadratic_equation 1,-3,-1]
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x = (3+sqrt(13))/2
x = (3-sqrt(13))/2
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D. Using synthetic substitution, which of the possible rational roots is actually a root of the equation?
E. Find the irrational roots of the equation(hint:ust the quadratic formula to solve the depressed equation.