Question 216484
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I used a graphing program to plot the points and then did a polynomial curve fit -- just because it sort of looked like it might fit a parabola.  I came up with:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ -\frac{x^2}{3}\ +\ 7x\ +\ \frac{4}{3}]



John
*[tex \LARGE e^{i\pi} + 1 = 0]
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