Question 216089
A survey of 865 voters in one state reveals that 408 favor approval of an issue before a legislature. Construct the 95% confidence interval for the true proportion of all voters in the state who favor approval. 
I know the answer is 12.74
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sample proportion = 408/865 = 0.47
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standard error = 1.96*sqrt[0.47*0.53/865] = 0.033
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95% CI: 0.47-0.33 < p < 0.47+0.33
95% CI: 0.14 < p < 0.8
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Cheers,
Stan H.