Question 216256
(x-2)^2=28


(x - 2)(x - 2) = 28 ------- breaking down {{{(x - 2)^2}}}


{{{x^2 - 4x + 4 = 28}}} ------- Expanding left side of equation


{{{x^2 - 4x + 4 - 28 = 0}}} ----- subtracting 28 from both sides of equation


{{{x^2 - 4x - 24 = 0}}}

Using the quadratic equation,{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}, we get:


x  = 7.291502622, or -3.291502622


OR


{{{(x-2)^2 = 28}}}


{{{(sqrt(x - 2))^2 = sqrt(28)}}}


x  -  2  = +/- 5.291502622


x = 5.291502622 + 2 = {{{highlight_green(7.291502622)}}} or x = - 5.291502622 + 2 = {{{highlight_green(-3.291502622)}}}