Question 216310
Find two consecutive odd integers in which the sum is equal to one or more than three times the smallest.


Step 1.  Let n be one odd integer and let n+2 be the next consecutive integer.


Step 2.  Let 3n be three times the smallest.


Step 3.  Then n+n+2=1+3n or 2n+2=1+3n.  Then n=1 and n+2=3.


Step 4. ANSWER:  The numbers are 1 and 3.


I hope the above steps were helpful.


For FREE Step-By-Step videos in Introduction to Algebra, please visit 

http://www.FreedomUniversity.TV/courses/IntroAlgebra and for Trigonometry visit 

http://www.FreedomUniversity.TV/courses/Trigonometry.


Good luck in your studies!


Respectfully,
Dr J