Question 216122
Find the equation of each line in y=mx+b form (-3,5) slope 1/5


Step 1.  The equation of the line given as y=mx+b is the slope-intercept form where m is the slope at b is the y-intercept when x=0 or at point (0,b).


Step 2.  Since the slope is {{{m=1/5}}}, we have {{{y=1*x/5+b}}}.  To get the y-intercept b, substitute x=-3 and y=5 since this line passes through the point (-3,5).


{{{5=-3/5+b}}}


Multiply 5 to both sides to get rid of denominator.


{{{5*5=-3+5b}}}


{{{25=-3+5b}}}


Add 3 to both sides of the equation


{{{25+3=-3+5b+3}}}


{{{28=5b}}}


Divide 5 to both sides of the equation


{{{28/5=5b/5}}}


{{{b=28/5}}}


Step 3.  ANSWER:  The equation is {{{y=x/5+28/5}}}


The graph is shown below.  Note the y-intercept at x=0 and the slope of 1/5 which means five units to the left, then one unit up.


{{{graph( 600, 600, -10, 10, -10, 10, x/5+28/5 )}}}


I hope the above steps were helpful.


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http://www.FreedomUniversity.TV/courses/Trigonometry.


Good luck in your studies!


Respectfully,
Dr J