Question 216086
what is x?
sqrt (3x+1)+ sqrt (2x+4)= 3 
i subtracted>>>sqrt (2x+4) from both sides and got >>>>sqrt (3x+1)= 3 -sqrt (2x+4)
then i squared both sides to remove the radical and got>> 
3x+1= (3-(sqrt(2x+4)(3-sqrt(2x+4)then i did that and got
3x+1= 9-6 sqrt(2x+4) +2x+4
then i added 9+4 and got >> 3x+1=13-6 sqrt(2x+4) +2x
then i subtrcated 2x from each side and got>>> x+1=13-6 sqrt(2x+4)
then i subtracted 1 from each side and got>> x=12-6sqrt(2x+4)
added 6sqrt(2x+4) to each side and got>>> 6sqrt(2x+4)+x=12
then i subtracted x from both sides and got>>> 6sqrt(2x+4)=12-x
then i squared both sides to remove the radical n got
36(2x+4)=(12-x)(12-x)
72x+144=144-12x-12x+x^2
72x+144= 144-24x=x^2
-72x-144 -144-72x 
0=-96x+x^2 
0=x^2+96  -96x not +
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You left off the x in 96x
x^2 - 96x = 0
x = 0
x = 96
Close, one slipup