Question 216038
A stdy involves 608 randomly selected deaths, with 26 of them caused by accidents. Construct a 98% confidence interval for the true percentage of all deaths that are caused by accidents. 
I know the answer is 2.36%
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sample proportion = 26/608 = 0.043
standard error = E = 2.3263*sqrt[(0.043)(0.957)/608] = 0.019..
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98% CI: 0.043-0.019 < p < 0.043+0.019
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98% CI: 0.024 < p < 0.062
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Cheers,
Stan H.