Question 215836
It looks like the equation relating the temperature (T, the dependent variable) and the altitude (A, the indepedent variable) would be:
{{{T = (-2A/1000)+15}}}
Let's check:
{{{T = (-2A/1000)+15}}} Substitute A = 0.
{{{T = (-2(0)/1000)+15}}}
{{{T = 15}}} OK.
{{{T = (-2A/1000)+15}}} Substitute A = 1000.
{{{T = (-2(1000))/1000)+15}}}
{{{T = -2+15}}}
{{{T = 13}}} OK.
{{{T = (-2A/1000)+15}}} Substitute A = 3000.
{{{T = (-2(2000)/1000)+15}}}
{{{T = -4+15}}}
{{{T = 11}}}OK.
{{{T = (-2A/1000)+15}}} Substitute A = 5000.
{{{T = (-2(5000)/1000)+15}}}
{{{T = -10+15}}}
{{{T = 5}}}
So the predicted temperature at an altitude of 5000 feet would be 5 degrees C.