Question 215773
Let x = the first (smallest) integer, then (x+2) is the next consecutive integer and (x+3) is the third (largest) consecutive integer.
{{{2x+3(x+2) = 126}}} "...the sum of twice the smallest integer and three times the largest is 126."
{{{2x+3x+6 = 126}}}
{{{5x+6 = 126}}} Subtract 6 from both sides.
{{{5x = 120}}} Divide both sides by 5.
{{{x = 24}}} and {{{x+1 = 25}}}, {{{x+2 = 26}}}
The three consecutive integers are: 24, 25, and 26.