Question 3675
To solve the problem use the formula for area of a triangle...

Area of a triangle:
{{{A=(1/2)b*h}}}

You may have some difficulty here multiplying mixed numbers.  The best option is to convert these. 

A B/C = {{{(A*C+B)/C}}}
so 
3 5/8 = {{{(3*8+5)/8=29/8}}}

You can do the same time thing with 2 1/2.

For example:
Same problem different numbers...
what is the area of a triangle with a base = 4 3/8 and a height = 3 1/2
{{{b=4&3/8 =(4*8+3)/8=35/8)}}}
{{{h=3&1/2 =(3*2+1)/2=7/2)}}}

{{{A=(1/2)b*h=(1/2)(35/8)(7/2)=245/32}}}

You can leave it in this form or if you need to make it back into a mixed number:
32 goes into 245 7 times with a remainder of 21.  So the answer is 7 21/32.

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There are other ways to do this problem as well.  
For instance... we could make the mixed fractions into an addition problems as so...

4 3/8 = (4+3/8)
3 1/2 = (3+1/2)

and then do the following
{{{A=(1/2)(4+3/8)(3+1/2)=(1/2)(12+3(3/8)+4(1/2)+(1/2)(3/8))=(1/2)(12+9/8+2+3/16)}}}
{{{9/8 = 8/8+1/8=1+1/8}}} and {{{1/8=2/16}}} so {{{9/8=1+2/16}}}
So:
{{{(1/2)(12+9/8+2+3/16)=(1/2)(14+(1+2/16)+3/16)=(1/2)(15+5/16)=15/2+5/32}}}
{{{15/2=14/2+1/2=7+1/2}}} and {{{1/2=16/32}}} so {{{15/2=7+16/32}}}
So:
{{{15/2+5/32=(7+16/32)+5/32=7+21/32}}}
Which is 7 21/32.
Pointless but might give some understanding.