Question 215763
Let x, x+2, x+4, x+6, x+8 be the five consecutive odd integers.
x+(x+8)=3(x+4)-1
2x+8=3x+12-1
2x-3x=11-8
-x=3
x=3/-1
x=-3 ans. for the lowest integer.
-3+2=-1 for the next integer. 
-3+4=1 for the middle integer.
-3+6=3 for the fourth imteger.
-3+8=5 for the largest integer.
Proof:
-3+5=3*1-1
2=3-1
2=2