Question 215647
Let x, x+1 & x+2 be the three integers.
x+2(x+1)+3(x+2)=62
x+2x+2+3x+6=62
6x=62-2-6
6x=54
x=54/6
x=9 ans. for the lowest integer.
9+1=10 ans. for the second integer.
9+2=11 ans. for the third integer.
9+2*10+3*11=62
9+20+33=62
62=62