Question 215542
Let x be the length of the side on the original square. Then 2x is the length on the larger one
{{{AreaOfSquare = Side^2}}}
{{{AreaOfOriginalSquare = x^2}}}
{{{AreaOfBigSqaure = (2x)^2 = 4x^2}}}
So the bigger square has 4 times the area of the original one