Question 215527
I am trying to solve a Algebraic fraction problem.  How to find the value of y in the equation

{{{3/y-2=8}}}  


Step 1.  Multiply y to both sides of the equation to get rid of denominator.



{{{y*(3/y-2)=8*y}}} 


{{{3-2y=8y}}}  


Step 2.  Add 2y to both sides of the equation to get variables on the right side and the numbers on the left side.


{{{3-2y+2y=8y+2y}}}


{{{3=10y}}}


Step 3.  Divide 10 to both sides of the equation.


{{{3/10=10y/10}}}


{{{y=3/10}}}


Step 4.  Check by substitution of {{{y=3/10}}} into {{{3/y-2=8}}}.


{{{3/(3/10)-2=8}}} which is a true statement.


Step 5.  ANSWER is {{{3/10=0.3}}} 


I hope the above steps were helpful.


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Good luck in your studies!


Respectfully,
Dr J