<PRE><B>Question 215507</B>
Car A passes point O heading east at a constant rate of 40mi/h; car B passes the same point 1 hour later heading north at a constant rate of 60mi/h. 
---
Car A DATA:
rate = 40 mph ; time = t+1  hrs ; distance = rt = 40(t+1) miles
-------------------
Car B DATA:
rate = 60 mph ; time = t hrs ; distance = 60t miles
-------------------

Express the distance between the cars as a function of time t, where t is measured starting when car B passes point O.
---
Yes, use the Pythagorean Equation to get:
(distance between A and B) = sqrt[(60t)^2 + (40(t+1))^2]
d = 3600t^2 + 1600(t^2+2t+1)
=============================================================
Cheers,
Stan H. </PRE>