Question 29482
5x/2x+2 = 2x/3x+3 + 2x+3/x+1
Consider only the denominators
2x+2 = 2(X+1)
3x+3 = 3(X+1)
x+1 = 1(x+1)
Since X+1 is common to all, you cancel them all out!!!
5x/2 = 2x/3 + 2x+3/1
you only have to worry abt 1,2,3 whose LCM becomes 6
So basically your LCD is 6
can you solve from here?