Question 215435
The sum of two integers is ten. Three times the larger integer is three less than eight times the smaller integer. Find the integers
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Equation:
x + y = 10
3x = 8y-3
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Rearrange the equation:
x = 10-y
Substitute for x and solve for "y":
3(10-y) = 8y-3
30-3y = 8y-3
11y = 33
y = 3
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Since x = 10-y, x = 7
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Cheers,
Stan H.