Question 215309
The sum of thre numbers is 40. One number is 5 more than the second number.  It is twice the third number.  What are the numbers.


Let the second number be S

Then the first number is S + 5 since it is given that it's 5 more than the second number


And, since it's given that the 1st number is also twice the 3rd number, then the 3rd number = {{{(S + 5)/2}}}


Since it's also given that the 3 numbers total 40, then we'll have: {{{S + S + 5 + (S + 5)/2 = 40}}}


2S + 2S + 10 + S + 5 = 80 ------- Multiplying by LCD, 2


5S + 15 = 80


5S  =  65


{{{S = 65/5 = 13}}}


Therefore, the first number, or S + 5 is {{{highlight_green(18)}}} (13 + 5), the second number, or S is {{{highlight_green(13)}}}, and the third {{{highlight_green(9)}}} ({{{18/2}}}).