Question 215253
To  multiply,  we  can  use  FOIL  with  the  first  two items,  but we  must  use  distribution  with  the  last.
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To  start,,,,(t+1)(2t-2)
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First  term,,,,(t)*(2t) = 2t^2
Outside  terms,,,(t)*(-2) = -2t
Inside  terms,,,,(1)*(2t) = 2t
Last  terms,,,,,,(1)*(-2) = -2
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we  can  combine  the  "t" terms,,,,-2t +2t =0
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The  result  is  (2t^2 -2 )
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To  complete  the  problem,,,,(t+4)*(2t^2 -2)
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Since  this  is  only  2x2  terms  we  could  foil  again,  but  let's use  distribution,  which  is  more  general.
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t*(2t^2-2) +4(2t^2-2)
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2t^3 -2t +8t^2 -8
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2t^3 +8t^2 - 2t -8,,,,,,final  answer
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check,,let  x=3,,,both  original  and  answer  = 112,,,,,ok
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