Question 215197
The equation of the line that goes through the point (2,8) and is parallel to the line 3x + 3y = 4 can be written in the form y = mx+b where m is:
and where b is: 
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Find the slope of 3x + 3y = 4 by putting it in slope-intercept form (that means solve for y).
3x + 3y = 4
3y = -3x + 4
y = -x + 4/3
Slope, m = -1
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All parallel lines have the same slope.
Use y-y1 = m*(x-x1) where (x1,y1) is the point
y-8 = -(x-2)
y = -x + 10