Question 215032
A ship travels 58 km on a bearing of 20 degrees, and then travels on a bearing of 110 degrees for 133 km. Find the distance from the starting point to the end of the trip, to the nearest kilometer.
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2 sides of a triangle are given, 58 and 133 km.
The change in heading from 020º to 110º is 90º, so it's a right triangle.
Use Pythagoras:
{{{s = sqrt(58^2 + 110^2)}}}
s = 124 km