Question 215047
 The product of two consecutive odd integers is 10 more than the square of the smaller integer. Find the integers.
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1st: 2x-1
2nd: 2x+1
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(2x-1)(2x+1) = (2x-1)^2+10
4x^2-1 = 4x^2 - 4x + 1 + 10
4x = 12
x = 3
1st = 2x-1 = 5
2nd = 2x+1 = 7
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Cheers,
Stan H.