Question 215016
Note: I'm assuming that the given lengths of "A=10cm and B=6cm" are the lengths of the semi-major and semi-minors axes.



The area of an ellipse is simply {{{A=pi*ab}}} where 'A' is the area, 'a' is the length of the semi-major axis, and 'b' is the length of the semi-minor axis.



So in this case, just plug in {{{a=10}}}, {{{b=6}}} and 3.142 for {{{pi}}} to get {{{A=(3.142)(10)(6)=188.52}}}



So the area is roughly 188.52 square centimeters.