Question 214985
Note: *[Tex \LARGE \left(x_{1}, y_{1}\right)] is the first point *[Tex \LARGE \left(-2,3\right)]. So this means that {{{x[1]=-2}}} and {{{y[1]=3}}}.

Also, *[Tex \LARGE \left(x_{2}, y_{2}\right)] is the second point *[Tex \LARGE \left(1,-4\right)].  So this means that {{{x[2]=1}}} and {{{y[2]=-4}}}.



{{{m=(y[2]-y[1])/(x[2]-x[1])}}} Start with the slope formula.



{{{m=(-4-3)/(1--2)}}} Plug in {{{y[2]=-4}}}, {{{y[1]=3}}}, {{{x[2]=1}}}, and {{{x[1]=-2}}}



{{{m=(-7)/(1--2)}}} Subtract {{{3}}} from {{{-4}}} to get {{{-7}}}



{{{m=(-7)/(3)}}} Subtract {{{-2}}} from {{{1}}} to get {{{3}}}



So the slope of the line that goes through the points *[Tex \LARGE \left(-2,3\right)] and *[Tex \LARGE \left(1,-4\right)] is {{{m=-7/3}}}