Question 214880
Let the numbers be {{{a}}}, {{{b}}}, and {{{c}}}
given:
(1) {{{a + b + c = 147}}}
(2) {{{b = 2a + 4}}}
(3) {{{c = 3a - 5}}}
I can substitute (2) and (3) into (1)
(1) {{{a + b + c = 147}}}
{{{a + 2a + 4 + 3a - 5 = 147}}}
{{{6a - 1 = 147}}}
{{{6a = 148}}}
{{{a = 74/3}}}
This isn't a whole number. Are you sure you copied 
the problem right?