Question 214884
Remember  a^b/a^c = c^(b-c)
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(3)/(9) * a^7/a^5 * b^(-4) / b^5
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1/3 * a^(7-5) * b^( -4-5)
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(1/3)a^2 b^(-9),,,,,,and  b^(-1) = 1/b^(+1)
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(1/3) (a^2)/ (b^9)
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(a^2) /{ 3 * b^9 }
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