Question 214887
Sum of three consecutive odd integers plus twice the smallest odd integer is 91.  Find the integer.


Step 1.  Let n be an odd integer and let n+2 and n+4 be the next two consecutive odd integers.


Step 2.  Let n+n+2+n+4 be the sum of the three consecutive odd integers.


Step 3.  Let 2n be twice the smallest odd integer


Step 4.  n+n+2+n+4+2n=91  as given by the problem statement


Step 5.  The following will solve the equation in Step 4.


*[invoke explain_simplification "n+n+2+n+4+2n=91" ]


With n=17, then n+2=19 and n+4=21.


Step 6.  ANSWER:  The integers are  17, 19 and 21 with 17 as the smallest odd integer.


I hope the above steps were helpful.


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Good luck in your studies!


Respectfully,
Dr J